Boltzmann constant: Difference between revisions

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the so-called equipartition theorem,
the so-called equipartition theorem,


KE<sub>avg</sub> = 3/2 ''kT''
:<math> KE_\mathrm{avg} = \left(\frac{3}{2}\right) kT</math><ref>http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kintem.html</ref><br />


Where KE<sub>avg</sub> is the average [[kinetic energy]] of the particle, ''k'' is the Boltzmann Constant, and ''T'' is the [[temperature]] in [[kelvin]].
Where KE<sub>avg</sub> is the average [[kinetic energy]] of the particle, ''k'' is the Boltzmann Constant, and ''T'' is the [[temperature]] in [[kelvin]].

Revision as of 09:44, 31 December 2007

The Boltzmann constant k (also kB) is the ratio of the molar gas constant R to Avogadro's constant NA. It can be thought of as the gas constant for a single molecule (or even for an arbitrary particle in a colloidal solution) rather than for a mole[1].

The Boltzmann Constant is illustrated in the equation for the translational kinetic energy of a particle in thermal equilibrium with its surroundings,[2] the so-called equipartition theorem,

[3]

Where KEavg is the average kinetic energy of the particle, k is the Boltzmann Constant, and T is the temperature in kelvin.

According to NIST[4] the Boltzmann Constant has a value of 1.3806504 x 10-23 J/K with a standard uncertainty of 0.0000024 x 10-23 J/K and a relative uncertainty of 1.7 x 10-6 (this is represented by the concise form 1.380 6504(24) x 10-23 J/K

The Boltzmann Constant can also be represented in alternative units as 8.617385 x 10-5 eV/K

References