User talk:Paul Wormer/scratchbook1

PD Image
Equation for plane. X is arbitary point in plane; $\scriptstyle {\vec {\mathbf {a} }}$ and $\scriptstyle {\hat {\mathbf {n} }}$ are collinear.

In analytic geometry several closely related algebraic equations are known for a plane in three-dimensional Euclidean space. One such equation is illustrated in the figure. Point X is an arbitrary point in the plane and O (the origin) is outside the plane. The point A in the plane is chosen such that vector

${\vec {a}}\equiv {\overrightarrow {OA}}$

is orthogonal to the plane. The collinear vector

${\vec {n}}\equiv {\frac {\vec {a}}{a}}\quad {\hbox{with}}\quad a\equiv {|{\vec {a}}|}$

is a unit (length 1) vector normal (perpendicular) to the plane. Evidently a is the distance of O to the plane. The following relation holds for an arbitrary point X in the plane

$\left({\vec {r}}-{\vec {a}}\right)\cdot {\vec {n}}=0\quad {\hbox{with}}\quad {\vec {r}}\equiv {\overrightarrow {OX}}\quad {\hbox{and}}\quad {\vec {r}}-{\vec {a}}={\overrightarrow {AX}}.$

This equation for the plane can be rewritten in terms of coordinates with respect to a Cartesian frame with origin in O. Dropping arrows for component vectors (real triplets) that are written bold, we find

$\mathbf {r} \cdot \mathbf {n} =\mathbf {a} \cdot \mathbf {n} \Longleftrightarrow xu+yv+zw=a$

with

$\mathbf {a} =(u,\;v,\;w),\quad \mathbf {r} =(x,\;y,\;z),\quad {\hbox{and}}\quad \mathbf {a} \cdot \mathbf {n} =\mathbf {a} \cdot {\frac {\mathbf {a} }{a}}=a={\sqrt {u^{2}+v^{2}+w^{2}}}.$

Conversely, given the following equation for a plane

$ax+by+cz=d\,$

it is easy to derive the same equation. Write

$\mathbf {r} =(x,\;y,\;z),\quad \mathbf {f} =(a,\;b,\;c),\quad {\hbox{and}}\quad \mathbf {a} \equiv {\frac {d}{\mathbf {f} \cdot \mathbf {f} }}\mathbf {f} .$

It follows that

$\mathbf {f} \cdot \mathbf {r} =d=\mathbf {f} \cdot \mathbf {a} .$

Hence we find the same equation,

$\mathbf {f} \cdot (\mathbf {r} -\mathbf {a} )=0\;\Longrightarrow \;\mathbf {n} \cdot (\mathbf {r} -\mathbf {a} )=0\quad {\hbox{with}}\quad \mathbf {n} ={\frac {\mathbf {f} }{\sqrt {a^{2}+b^{2}+c^{2}}}}$

where f , a, and n are collinear. The equation may also be written in the following mnemonically convenient form

$\mathbf {a} \cdot (\mathbf {r} -\mathbf {a} )=0,$

which is the equation for a plane through a point A perpendicular to ${\overrightarrow {OA}}$.