Talk:Sturm-Liouville theory: Difference between revisions

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imported>Paul Wormer
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imported>Paul Wormer
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It seems to me that the article contains an error. Consider the equation:
It seems to me that the article contains an error. Consider the equation:
: <math>L  u  = {1 \over w(x)} \left(-{d\over dx}\left[p(x){du\over dx}\right]+q(x)u \right)</math>
: <math>L  u  = {1 \over w(x)} \left(-{d\over dx}\left[p(x){du\over dx}\right]+q(x)u \right)</math>
Contrary to what is implied in the article, the operator ''L'' is ''not'' self-adjoint, unless 1/''w''(''x'') commutes with the operator to its right.  This in general not the case. The proper way to transform is
Contrary to what is implied in the article, the operator ''L'' is ''not'' self-adjoint, unless 1/''w''(''x'') commutes with the operator to its right.  This is in general not the case. The proper way to transform is
:<math>
:<math>
L u = wu\; \Longrightarrow\; w^{-1/2} L w^{-1/2} w^{1/2} u = w^{1/2} u \; \Longrightarrow\;   
L u = wu\; \Longrightarrow\; w^{-1/2} L w^{-1/2} w^{1/2} u = w^{1/2} u \; \Longrightarrow\;   

Revision as of 03:10, 14 October 2009

This article is basically copied from an external source and has not been approved.
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 Definition A special second order linear ordinary differential equation. [d] [e]
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Numbered equations

Hi Daniel,

I had to transform the templates provided in the WP article for numbered equations into plain old wikimarkup. I attempted to bring these templates over from WP, but they called many other templates and when I got them all over, the combined result didn't work. I decided to use a simple bit of html that defined a span with right justification and also defined an anchor. To reference the equation you then only need to insert a mediawiki markup referencing the anchor. It wouldn't be hard to turn this all into two templates if you think that would be useful. Dan Nessett 19:28, 2 September 2009 (UTC)


Redacted comment. I see it now.

Error

It seems to me that the article contains an error. Consider the equation:

Contrary to what is implied in the article, the operator L is not self-adjoint, unless 1/w(x) commutes with the operator to its right. This is in general not the case. The proper way to transform is

with

Since w(x) is positive-definite w(x)−½ is well-defined and real. The operator is self-adjoint.

--Paul Wormer 08:09, 14 October 2009 (UTC)