Talk:Sequence: Difference between revisions

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imported>Catherine Woodgold
(Simple example?)
imported>Aleksander Stos
Line 26: Line 26:
:<math>1 + i, 2 + 3i, 3 + 5i</math>
:<math>1 + i, 2 + 3i, 3 + 5i</math>
--[[User:Catherine Woodgold|Catherine Woodgold]] 08:20, 28 April 2007 (CDT)
--[[User:Catherine Woodgold|Catherine Woodgold]] 08:20, 28 April 2007 (CDT)
::I wouldn't object any proposed changes, the formal definition above included (well I thought a while about this definition and I think there would be no harm if the term "subset" gets deleted). As for 0 in naturals, nothing is "globally" decided, so probably both solutions are possible (I'd start with 1).--[[User:Aleksander Stos|AlekStos]] 11:55, 28 April 2007 (CDT)

Revision as of 11:55, 28 April 2007


Article Checklist for "Sequence"
Workgroup category or categories Mathematics Workgroup [Categories OK]
Article status Developing article: beyond a stub, but incomplete
Underlinked article? Yes
Basic cleanup done? Yes
Checklist last edited by --AlekStos 02:57, 10 March 2007 (CST)

To learn how to fill out this checklist, please see CZ:The Article Checklist.





defined on the natural numbers

I would like to change this:

"Formally, given any set X, an infinite sequence is a function (f, say) defined on a subset of natural numbers with values in X. "

to this:

"Formally, given any set X, an infinite sequence is a function (f, say) defined on the natural numbers , with values in X. "

(I'm not sure whether to include zero in the natural numbers.) --Catherine Woodgold 08:12, 28 April 2007 (CDT)

Simple example?

This is given as a "simple example" of a sequence of complex numbers:

How about a simpler example, where it's easy to predict the next term? e.g.

--Catherine Woodgold 08:20, 28 April 2007 (CDT)

I wouldn't object any proposed changes, the formal definition above included (well I thought a while about this definition and I think there would be no harm if the term "subset" gets deleted). As for 0 in naturals, nothing is "globally" decided, so probably both solutions are possible (I'd start with 1).--AlekStos 11:55, 28 April 2007 (CDT)