Talk:Binomial theorem: Difference between revisions

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imported>Anthony Argyriou
(checklist)
 
imported>David E. Volk
(suggest change in formula for clarity)
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status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. [[User:Anthony Argyriou|Anthony Argyriou]] 17:23, 18 July 2007 (CDT)
status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. [[User:Anthony Argyriou|Anthony Argyriou]] 17:23, 18 July 2007 (CDT)
While the definition is strictly true, it seems written backwards, in that if you actually do
the sum for (x+y)^2 the answer you get as the equation is written is y^2 + 2xy + x^2. Of course you can rearrange
to get x^2 + 2xy + y^2.  Another way to write it would be
x^(n-k)y^(k), in which case you directly get the answers as shown in the examples.
[[User:David E. Volk|David E. Volk]]

Revision as of 15:44, 25 July 2007


Article Checklist for "Binomial theorem"
Workgroup category or categories Mathematics Workgroup [Categories OK]
Article status Developing article: beyond a stub, but incomplete
Underlinked article? Yes
Basic cleanup done? Yes
Checklist last edited by Anthony Argyriou 17:23, 18 July 2007 (CDT)

To learn how to fill out this checklist, please see CZ:The Article Checklist.





status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. Anthony Argyriou 17:23, 18 July 2007 (CDT)


While the definition is strictly true, it seems written backwards, in that if you actually do the sum for (x+y)^2 the answer you get as the equation is written is y^2 + 2xy + x^2. Of course you can rearrange to get x^2 + 2xy + y^2. Another way to write it would be

x^(n-k)y^(k), in which case you directly get the answers as shown in the examples.

David E. Volk