< Erlang (programming language) | TutorialsRevision as of 06:07, 8 August 2009 by imported>Tom Morris
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gb_sets
Why go to the bother of using a structure other than a list for sets?
Normally for small sets, lists work fine. But operations on lists
are slow, and awkward if the list is long. Long depends on the machine
and available memory. Generally speaking, a balanced binary tree
will give the fastest access time of most any alternative data structure.
Generally the speed is O(log(n)) for a binary tree. Whereas a list is
order O(n).
Using gb_sets
Lets create a genalized balanced set from a list.
1> A = gb_sets:from_list([1,2,3,4,5]).
{5,{3,{2,{1,nil,nil},nil},{5,{4,nil,nil},nil}}}
3
/ \
2 5
/ / \
1 4
Now we remove an element.
2> B = gb_sets:del_element(1,A).
{4,{3,{2,nil,nil},{5,{4,nil,nil},nil}}}
3
/ \
2 5
/ \
4
And remove another element.
4> C = gb_sets:del_element(2,B).
{3,{3,nil,{5,{4,nil,nil},nil}}}
3
/ \
5
/ \
4
Now we should balance the tree to keep our speed maximized.
5> D = gb_sets:balance(C).
{3,{4,{3,nil,nil},{5,nil,nil}}}
4
/ \
3 5