Superfunction is smooth exstension of iteration of other function for the case of non-integer number of iterations.
Roughly, if, for some constant
,
![{\displaystyle {{S(z)} \atop \,}{= \atop \,}{{\underbrace {f{\Big (}f{\big (}...f(t)...{\big )}{\Big )}} } \atop {z\mathrm {~evaluations~of~function~} f\!\!\!\!\!\!}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/b3f6e16c771deba9268f994fa2dc24975a6a684f)
then
can be interpreted as superfunction of function
.
Such definition is valid only for positive integer
.
Extensions
The recurrence above can be written as equations
![{\displaystyle S(z\!+\!1)=f(S(z))~\forall z\in \mathbb {N} :z>0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/33ee986b7a1baad96b9923b557861ec4ce295b37)
.
Instead of the last equation, one could write
![{\displaystyle S(0)=f(t)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/c1c4ac95fd846adb8a716554e61b3b0f153d2973)
and extend the range of definition of superfunction
to the non-negative integers.
Then, one may postulate
![{\displaystyle S(-1)=t}](https://wikimedia.org/api/rest_v1/media/math/render/svg/9cff2064984f408a1503773df557cecf5d1cdb62)
and extend the range of validity to the integer values larger than
.
The following extension, for example,
![{\displaystyle S(-2)=f^{-1}(t)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/f97145a0325addbe5e29ccf01fd7528a3558d868)
is not trifial, because the inverse function may happen to be not defined for some values of
.
In particular, tetration can be interpreted as super-function of exponential for some real base
; in this case,
![{\displaystyle f=\exp _{b}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/666e70af6263d0f79972881278ae64c616fb9fcd)
then, at
,
.
but
.
For extension to non-integer values of the argument, superfunction should be defined in different way.
Definition
For complex numbers
and
, such that
belongs to some domain
,
superfunction (from
to
) of holomorphic function
on domain
is
function
, holomorphic on domain
, such that
![{\displaystyle S(z\!+\!1)=f(S(z))~\forall z\in D:z\!+\!1\in D}](https://wikimedia.org/api/rest_v1/media/math/render/svg/22010256d09133270ba2f0b0ba43bee1aa31f175)
.
Examples
Addition
Chose a complex number
and define function
with relation
.
Define function
with relation
.
Then, function
is superfunction (
to
)
of function
on
.
Multiplication
Exponentiation
is superfunction (from 1 to
) of function
.
Abel function
Inverse of superfunction can be interpreted as the Abel function.
For some domain
and some
,
,
Abel function (from
to
) of function
with respect to superfunction
on domain
is holomorphic function
from
to
such that
![{\displaystyle S(A(z))=z~\forall z\in E}](https://wikimedia.org/api/rest_v1/media/math/render/svg/cd21c0d3137783e28ca068394dfefe1bc4d95b22)
![{\displaystyle A(u)=c}](https://wikimedia.org/api/rest_v1/media/math/render/svg/97d28d30293c4c1db480ad99d2bc609b61cd52a0)
The definitionm above does not reuqire that
; although, from properties of holomorphic functions, there should exost some subset
such that
. In this subset, the Abel function satisfies the Abel equation.
Abel equation
The Abel equation is some equivalent of the recurrent equation
![{\displaystyle F(S(z))=S(z\!+\!1)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/c46c1fec92905975d3357b06f7929f600c760a56)
in the definition of the superfunction. However, it may hold for
from the reduced domain
.
Applications of superfunctions and Abel functions