CZ Talk:Ombudsman/Archive 1/Election process: Difference between revisions

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imported>Peter Jackson
imported>Dan Nessett
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Would this satisfy your idea of public availability? [[User:Peter Jackson|Peter Jackson]] 09:59, 2 March 2012 (UTC)
Would this satisfy your idea of public availability? [[User:Peter Jackson|Peter Jackson]] 09:59, 2 March 2012 (UTC)
::Well, I don't think so, but perhaps I am wrong. For someone to run the algorithm independently, wouldn't they need all of the preference information? For example,
::*Candidate A: 25 1st preferences, 20 2nd preferences, 10 3rd preferences.
::*Candidate B: 16 1st preferences, 7 2nd preferences, 32 3rd preferences.
::*Candidate C: 12 1st preferences, 3 2nd preferences, 40 3rd preferences. [[User:Dan Nessett|Dan Nessett]] 18:53, 2 March 2012 (UTC)


Now to STV, which is a more complicated version of the same method. This is for when you're filling more than 1 place together: 2 or 3 seats on MC or EC. Let's take 3 as an example. Start by counting the number of valid ballots. Divide by 4. That's the quota. Anyone with at least that many votes is necessarily elected. (It's obviously impossible for too many to be so, unless all the votes are equally split among 4 candidates, in which case any election method requires coin-tossing.) If anyone is so elected, you redistribute their surplus votes, that is, the difference between what they got and the quota. (If there's more than 1, start with the one with most votes.) You do this by a proportion sum, which is where a pocket calculator comes in handy. E.g., if the quota is 5 and someone gets 7 votes, then each vote is transferred to the next preference, but marked down to count as 2/7 of a vote. If, however, the number of votes with a further preference marked is less than the surplus, you don't mark them up to compensate.
Now to STV, which is a more complicated version of the same method. This is for when you're filling more than 1 place together: 2 or 3 seats on MC or EC. Let's take 3 as an example. Start by counting the number of valid ballots. Divide by 4. That's the quota. Anyone with at least that many votes is necessarily elected. (It's obviously impossible for too many to be so, unless all the votes are equally split among 4 candidates, in which case any election method requires coin-tossing.) If anyone is so elected, you redistribute their surplus votes, that is, the difference between what they got and the quota. (If there's more than 1, start with the one with most votes.) You do this by a proportion sum, which is where a pocket calculator comes in handy. E.g., if the quota is 5 and someone gets 7 votes, then each vote is transferred to the next preference, but marked down to count as 2/7 of a vote. If, however, the number of votes with a further preference marked is less than the surplus, you don't mark them up to compensate.
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Supplementary note: on the question of deciding which equal bottom candidate is eliminated, note that one common case where it makes no difference (in AV at least) is where, for example, the 2 bottom candidates have 1 vote each and the next up has 3 or more. [[User:Peter Jackson|Peter Jackson]] 10:18, 2 March 2012 (UTC)
Supplementary note: on the question of deciding which equal bottom candidate is eliminated, note that one common case where it makes no difference (in AV at least) is where, for example, the 2 bottom candidates have 1 vote each and the next up has 3 or more. [[User:Peter Jackson|Peter Jackson]] 10:18, 2 March 2012 (UTC)
::From your description it appears voters specify preferences as in AV voting. However, it isn't clear from your description how these preferences are used. For example, you write, "Start by counting the number of valid ballots. Divide by 4. That's the quota. Anyone with at least that many votes is necessarily elected." Do you mean anyone with at least that many 1st preference votes is necessarily elected? Or do you mean something else?
::More generally, your description, while useful in giving the "flavor" of the vote counting algorithm is more indicative than declarative. Surely, there is a precise definition of the algorithm somewhere that you can cite.
::Eliding for the moment the question of whether someone with little or no experience in algorithm specification/use could implement STV with pencil and paper, it isn't clear to me from the general description you give what exactly it achieves. I was under the impression that STV eliminated the possibility of tie votes. But, it appears not. Right now, if we have a tie vote (which, by the way, has never happened), we execute a run-off election. You suggest using a random draw to break ties. We could change our procedures to use a random draw and eliminate run-off elections, so STV doesn't appear to provide any advantage in that regard. So, 1) what problem does STV solve; and 2) can you provide any evidence that this problem exists in our community? [[User:Dan Nessett|Dan Nessett]] 18:53, 2 March 2012 (UTC)

Revision as of 12:53, 2 March 2012

Report of Election Observer 2010

Please note the report I made as election observer after the 2010 elections Gareth Leng 09:51, 1 February 2012 (UTC)

Referendum on elections

So this is an instant-runoff system? The idea is to transfer votes from eliminated candidates? John Stephenson 13:17, 27 February 2012 (UTC)

Referendum A (election of unopposed candidates)

Please also note that Referendum A had slightly more support than Referendum B, and got a majority, but failed because it did not gain the two-thirds necessary to modify the Charter. However, there is clear support for the idea of allowing single candidates to be elected unopposed and something like this ought to be implemented to avoid endless by-elections. John Stephenson 13:17, 27 February 2012 (UTC)

Reservists

Another way to avoid frequent by-elections is to fill vacant seats by offering them to unsuccessful candidates. I do not think that having reservists is a good idea, however, because it is likely that in some cases these will be people whose candidacies attracted little support. Actually, allowing the Combined Council to make interim appointments until the next election might be best. John Stephenson 13:17, 27 February 2012 (UTC)

STV and Instant-runoff

I prefer the single-transferable vote and instant-runoff systems. Regarding STV, a proportional-representation system is the only way to ensure that the winners reflect the preferences of the voters and that votes are not wasted. Even if someone is 2nd or 3rd choice, they are still a candidate who the voter is satisfied with. Low 1st choices can, if necessary, be dealt with by imposing a minimum threshold such as the 25% in the referendum. STV also reduces the likelihood of a tie, since they can be broken with 2nd and subsequent preferences. With non-transferable votes, the only options are to re-run the elections or draw lots, which are truly last-resort options for STV.

The system is somewhat more complex than simple-majority voting but there is software to do the sums. The problems that occurred when STV was used in the first post-Charter elections were actually caused by the fact that people were allowed to contest two groups of seats and then give a preference, such that the order that names were removed affected the final results. But this was not a problem of STV itself.

I think I am the first elected member to get in without ever receiving an absolute majority (Hayford got the same number of votes as me, but he also got in previously under STV). I do not feel that I have a mandate, which is why I don't make casting votes on the EC. STV or another transferable system would have avoided this. John Stephenson 13:17, 27 February 2012 (UTC)

Writing here personally, not as a member of the MC, I oppose any voting system that requires software to analyze results. My objection is that such systems fail to provide transparency. If a voting system is so complex that a typical non-technical member can't determine the outcome from published voting information, then those members must trust an algorithm they neither understand nor are able to execute. This would have a chilling effect on election participation rates and would make it very difficult if not impossible for the election committee to adequately explain the election results.
In addition, the mandatory use of vote counting software implies requisite skills that would likely dissuade a large proportion of the community from serving on election committees. This would increase the difficultly of finding citizens willing and able to serve as committee members. Dan Nessett 19:40, 27 February 2012 (UTC)
Now that ballots are no longer to be destroyed soon after the count, the results are there should anyone demand a recount. I see no reason why an explanation could not be given of how votes were redistributed. Also, I believe that voter turnout has actually gone down since simple-majority voting has been used. As for people being dissuaded from acting as election committee participants, if someone is unwilling to participate because they don't want to get involved with software that is not actually that difficult to use, I really don't want them counting votes at all. What would such a person do in the event of a discrepancy even in a simple-majority contest? John Stephenson 07:08, 28 February 2012 (UTC)
Looking at the last few election results it would appear that the election committee could have counted them all on their fingers and toes, and the amount of digits they might need for such a task is getting fewer each time, so we are not discussing whether our new voting system would be so complex as to confound any of our current members, but instead wondering if with more members any new voting system might be better software-driven rather than limited by how many limbs the election committee might have.
If any concerns about software are about finding people able to use (probably simple) software to verify election results then don't worry, if we have enough voters to make software a necessity we will have enough citizens to find one or two not frightened of using it.
As for whether to use a preference system, of course we should. We've already seen the problems our current system has. It produced an alternate that the MC refused to allow to serve office. Their reasoning appeared to be that the alternate didn't get enough support? That being the case it would appear they used the STV system for judging suitability when useful. Although they did keep secret and destroy the results back in those days so it is hard to be sure.
The only reasoning I've heard against a new system is that it is either complex or un-American (that really is something that has been said on the forums), but if we attract enough members to make software a requirement there will almost certainly be a large portion of them that won't be worried by either of these arguments. David Finn 08:23, 28 February 2012 (UTC)
=> John Stephenson - Your arguments have several flaws. First, my point was someone should be able to determine the results "from published voting information." The raw ballots are never released for public display, since that would destroy the whole notion of a secret ballot. No matter how long ballots are retained, transparency requires the ability of non-technical members to determine the results from published information without the intervention of software, the operation of which they do not understand. Any voting system that cannot provide such transparency is flawed.
Second, what is simple to use is an objective judgment. What might be simple for someone with training in the sciences or engineering may not be simple for someone without such a background. Limiting election committee members to only those with technical skills introduces a tendency toward elitism and technocracy that could discourage those in the arts to participate in the project.
Third, even those with a technical background may have reservations about using software to determine the results of an election. I have a Ph.D. in computer science and have the skills necessary to understand how software works. However, taking the time to convince myself that a program correctly implements some non trivial vote tallying algorithm (and taking the time to learn and understand that algorithm) is not something I wish to do. I imagine many others feel the same way.
Fourth, there were 72 ballots cast in the charter referendum, 46 ballots cast in the October, 2010 election (which did not use simple majority voting), 40 ballots cast in the June, 2011 election, 14 ballots cast in the October, 2011 special election and 24 ballots cast in the December, 2011 election. Taking the special election as an outlier, participation has monotonically decreased over the past year and a half. If the use of majority voting is the cause of this, why was there a decrease in the October 2010 election? What evidence exists that use of simple majority voting has anything to do with this decrease? As far as I can see, no evidence supports this conclusion. Dan Nessett 19:40, 28 February 2012 (UTC)
I'm inclined to agree with your last comment.
I'm not sure what you mean precisely by verifiability from published information. The usual practice for STV elections in real life is to publish the totals for each stage. That is, you'd first list the numbers of first preferences for each candidate and then say whether anyone has been elected straight off. If so, you say how their surplus is redistributed. Otherwise, you say who's eliminated and how their votes are redistibuted. Would that be enough for you, or would you want a listing of all preferences on each ballot cast? Even the latter doesn't involve publishing the identity of the voter, or even correlating ballots in simultaneous elections.
STV procedure really isn't that complicated. I could easily work it out myself by hand, without software. So presumably could Peter. So very likely could David. And that's without any new training. You or anyone else here could do it if they want to learn. Peter Jackson 11:24, 1 March 2012 (UTC)

[unindent]

My concern is establishing a voting procedure that is so mysterious to non-technical members that they decide CZ isn't for them, If the algorithm of any voting method is easily implemented using pencil and paper ("easily" being defined as allowing someone without a technical background to execute it without a great deal of effort), then I would have no objection to it. While my view is we are attempting to fix something that isn't broken, if the majority of citizens want to use a voting method other than simple majority (which from the results of the referendum in the last election seems true) I will not oppose that. Dan Nessett 17:02, 1 March 2012 (UTC)

[added later] If STV voting satisfies the pencil and paper test, perhaps someone could explain how to to implement its algorithm with such implements using only published voting results (i.e., without having to divulge individual ballots). Dan Nessett 17:35, 1 March 2012 (UTC)
Let's distinguish between AV for a single post and STV proper for a batch of seats.
The former is really easy and shouldn't cause anyone any problems at all.
In the latter case, you'd probably prefer to use a pocket calculator to work out the proportions.
You still haven't said what you mean by "published voting results". Peter Jackson 18:42, 1 March 2012 (UTC)
For the purposes of this discussion, let's define "Published voting results" as those necessary to execute the algorithm. If a particular voting method requires the availability of individual ballots for this purpose, then I would say there is a significant conflict between it and the maintenance of secret ballot privacy. So, can you or someone else describe in detail how to use paper and pencil to implement both the AV and STV vote tallying methods? From this, we can determine whether the effort to implement those algorithms without software is within the capabilities of a non-technical member. Dan Nessett 19:05, 1 March 2012 (UTC)
Well, I'm still not clear what you mean, but I agree it's probably best to describe the method sufficiently here so everyone knows what we're talking about.

So let's start with AV, which is easier. You start by simply counting up the first preference votes. If someone has more than all the rest put together that's it. Otherwise you eliminate the person with least and pass on their votes to their next preferences. If they give no further preference then they no longer figure. If now someone has more than the remainder put together that's it. Repeat the process as many times as necessary. If a vote's next preference is for someone already eliminated you look for the next uneliminated preference. All really quite straightforward. The only problem you might get is if 2 candidates are equal bottom. Often it won't make a difference. If it does, what would happen in a real election is the Returning Officer would toss a coin, just as they would if there's a tie for the winner in an ordinary first-past-the-post election. Published results would look like this:

  • 1st count:
    • candidate A: 25 1st preferences
    • B: 16
    • C: 12
  • 2nd count: C is eliminated; 12 votes redistributed as follows:
    • A: 7
    • B: 3
    • no further preference: 2
  • result after 2nd count:
    • A: 32
    • B: 19

Would this satisfy your idea of public availability? Peter Jackson 09:59, 2 March 2012 (UTC)

Well, I don't think so, but perhaps I am wrong. For someone to run the algorithm independently, wouldn't they need all of the preference information? For example,
  • Candidate A: 25 1st preferences, 20 2nd preferences, 10 3rd preferences.
  • Candidate B: 16 1st preferences, 7 2nd preferences, 32 3rd preferences.
  • Candidate C: 12 1st preferences, 3 2nd preferences, 40 3rd preferences. Dan Nessett 18:53, 2 March 2012 (UTC)

Now to STV, which is a more complicated version of the same method. This is for when you're filling more than 1 place together: 2 or 3 seats on MC or EC. Let's take 3 as an example. Start by counting the number of valid ballots. Divide by 4. That's the quota. Anyone with at least that many votes is necessarily elected. (It's obviously impossible for too many to be so, unless all the votes are equally split among 4 candidates, in which case any election method requires coin-tossing.) If anyone is so elected, you redistribute their surplus votes, that is, the difference between what they got and the quota. (If there's more than 1, start with the one with most votes.) You do this by a proportion sum, which is where a pocket calculator comes in handy. E.g., if the quota is 5 and someone gets 7 votes, then each vote is transferred to the next preference, but marked down to count as 2/7 of a vote. If, however, the number of votes with a further preference marked is less than the surplus, you don't mark them up to compensate.

Once you've done this for all elected candidates you start eliminating the bottom ones as in AV.

An additional complication is that, as some votes disappear from the total because no further preferences are marked, you recalculate a reduced quota from the number of remaining votes (including the quota for elected candidates. Anyone reaching this reduced quota is elected, but only surpluses above the original quota are redistributed.

Published results would be similar to the above AV example, but obviously mre complicated. I hope this is all clear enough. Peter Jackson 10:16, 2 March 2012 (UTC)

Supplementary note: on the question of deciding which equal bottom candidate is eliminated, note that one common case where it makes no difference (in AV at least) is where, for example, the 2 bottom candidates have 1 vote each and the next up has 3 or more. Peter Jackson 10:18, 2 March 2012 (UTC)

From your description it appears voters specify preferences as in AV voting. However, it isn't clear from your description how these preferences are used. For example, you write, "Start by counting the number of valid ballots. Divide by 4. That's the quota. Anyone with at least that many votes is necessarily elected." Do you mean anyone with at least that many 1st preference votes is necessarily elected? Or do you mean something else?
More generally, your description, while useful in giving the "flavor" of the vote counting algorithm is more indicative than declarative. Surely, there is a precise definition of the algorithm somewhere that you can cite.
Eliding for the moment the question of whether someone with little or no experience in algorithm specification/use could implement STV with pencil and paper, it isn't clear to me from the general description you give what exactly it achieves. I was under the impression that STV eliminated the possibility of tie votes. But, it appears not. Right now, if we have a tie vote (which, by the way, has never happened), we execute a run-off election. You suggest using a random draw to break ties. We could change our procedures to use a random draw and eliminate run-off elections, so STV doesn't appear to provide any advantage in that regard. So, 1) what problem does STV solve; and 2) can you provide any evidence that this problem exists in our community? Dan Nessett 18:53, 2 March 2012 (UTC)