Talk:Binomial theorem: Difference between revisions

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imported>David E. Volk
(suggest change in formula for clarity)
imported>Subpagination Bot
m (Add {{subpages}} and remove checklist (details))
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|                abc = Binomial Theorem
|                cat1 = Mathematics
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|              status = 2
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|                  by = [[User:Anthony Argyriou|Anthony Argyriou]] 17:23, 18 July 2007 (CDT)
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status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. [[User:Anthony Argyriou|Anthony Argyriou]] 17:23, 18 July 2007 (CDT)
status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. [[User:Anthony Argyriou|Anthony Argyriou]] 17:23, 18 July 2007 (CDT)

Revision as of 07:22, 25 September 2007

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 Definition  for any natural number n. [d] [e]
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status is really about 2.5 - 2 for the elementary binomial theorem/formula, and 3 for the Newtonian. Anthony Argyriou 17:23, 18 July 2007 (CDT)


While the definition is strictly true, it seems written backwards, in that if you actually do the sum for (x+y)^2 the answer you get as the equation is written is y^2 + 2xy + x^2. Of course you can rearrange to get x^2 + 2xy + y^2. Another way to write it would be

x^(n-k)y^(k), in which case you directly get the answers as shown in the examples.

David E. Volk