Talk:Slater orbital: Difference between revisions

From Citizendium
Jump to navigation Jump to search
imported>Paul Wormer
No edit summary
 
imported>David E. Volk
(suggest explain position probability & normalization integral equals 1?)
Line 12: Line 12:


From WP (corrected and mainly written by me).--[[User:Paul Wormer|Paul Wormer]] 04:15, 22 August 2007 (CDT)
From WP (corrected and mainly written by me).--[[User:Paul Wormer|Paul Wormer]] 04:15, 22 August 2007 (CDT)
Paul, in the derivation of the normalization constant, perhaps you should explain how the normalization factor works, ie the sum of probably must add up to one, and the probability of being at any one point is ....
thus the integral equation over all space being equal to one.
[[User:David E. Volk|David E. Volk]] 13:30, 9 October 2007 (CDT)

Revision as of 13:30, 9 October 2007


Article Checklist for "Slater orbital"
Workgroup category or categories chemistry Workgroup, physics Workgroup [Please add or review categories]
Article status Developing article: beyond a stub, but incomplete
Underlinked article? Yes
Basic cleanup done? No
Checklist last edited by --Paul Wormer 04:15, 22 August 2007 (CDT)

To learn how to fill out this checklist, please see CZ:The Article Checklist.





From WP (corrected and mainly written by me).--Paul Wormer 04:15, 22 August 2007 (CDT)

Paul, in the derivation of the normalization constant, perhaps you should explain how the normalization factor works, ie the sum of probably must add up to one, and the probability of being at any one point is ....

thus the integral equation over all space being equal to one.

David E. Volk 13:30, 9 October 2007 (CDT)